document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290698>Question 290698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water needs to be added to 3 quarts of 96% alcohol to produce a mixture that is 75% alcohol? (concentration of alcohol in water is 0%)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210341 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are at least two approaches to this problem.<BR>\n" );
document.write( "From the view of alcohol or from the view of water.<BR>\n" );
document.write( "Alcohol view<BR>\n" );
document.write( "3*.96=(x+3)*.75<BR>\n" );
document.write( "x=.84 quarts\r<BR>\n" );
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document.write( "Water view<BR>\n" );
document.write( "3*(.04+x)=.25(x+3)<BR>\n" );
document.write( "x=.84 quarts\r<BR>\n" );
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document.write( "They serve as a check on each other.<BR>\n" );
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