document.write( "Question 34807: (x+4)^-1/3=4\r
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Algebra.Com's Answer #21034 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+%28x%2B4%29%5E%28-1%2F3%29+=+4+\"\r
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\n" ); document.write( "\n" ); document.write( "First, get rid of the negative power:
\n" ); document.write( "\"+1%2F%28x%2B4%29%5E%281%2F3%29+=+4+\"\r
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\n" ); document.write( "\n" ); document.write( "Now raise everything to cube, to remove the (1/3) power (which means a cube root). Also remember that \"1%5E3\" is just 1 still:
\n" ); document.write( "\"+%281%2F%28x%2B4%29%5E%281%2F3%29%29%5E3+=+4%5E3+\"
\n" ); document.write( "\"+1%2F%28x%2B4%29+=+4%5E3+\"
\n" ); document.write( "\"+1%2F%28x%2B4%29+=+64+\"
\n" ); document.write( "\"+1+=+64%28x%2B4%29+\"
\n" ); document.write( "\"+1+=+64x%2B256+\"
\n" ); document.write( "\"+-255+=+64x+\"
\n" ); document.write( "\"+-255%2F64+=+x+\"\r
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\n" ); document.write( "\n" ); document.write( "jon.
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