document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290678>Question 290678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Plane A and Plane B are 500 kilometres apart and flying towards each other. If plane A is travelling at a constant speed of 240 k/m and plane B is travelling at a constant speed of 360 k/m when will the planes meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #210332 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=210332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the distance they meet be x from A\r<BR>\n" );
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document.write( "time taken by A when they meet = x/240\r<BR>\n" );
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document.write( "Time taken by B when they meet = 500-x /360\r<BR>\n" );
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document.write( "These two times are the same\r<BR>\n" );
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document.write( "x/240 = 500-x / 360\r<BR>\n" );
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document.write( "360x =12000-240x\r<BR>\n" );
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document.write( "120x=12000\r<BR>\n" );
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document.write( "x=12000/120\r<BR>\n" );
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document.write( "x=100 km\r<BR>\n" );
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document.write( "100/240 \r<BR>\n" );
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document.write( "=10/24 *60 = 25 minutes\r<BR>\n" );
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document.write( " </SPAN>\n" );
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