document.write( "Question 290626: the perimeter of a rectangle is 128 metres. the length is 4 metres more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #210297 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "128=2(2W+4)+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "128=4W+8+2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "128=6W+8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "128-8=6W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120=6W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W=20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=2W+4=2(20)+4=40+4=44\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: width is 20 and length is 44 \n" ); document.write( " |