document.write( "Question 290626: the perimeter of a rectangle is 128 metres. the length is 4 metres more than twice the width. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #210297 by user_dude2008(1862)\"\" \"About 
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P=2L+2W\r
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\n" ); document.write( "\n" ); document.write( "128=2(2W+4)+2W\r
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\n" ); document.write( "\n" ); document.write( "128=4W+8+2W\r
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\n" ); document.write( "\n" ); document.write( "128=6W+8\r
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\n" ); document.write( "\n" ); document.write( "128-8=6W\r
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\n" ); document.write( "\n" ); document.write( "120=6W\r
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\n" ); document.write( "\n" ); document.write( "W=20\r
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\n" ); document.write( "\n" ); document.write( "L=2W+4=2(20)+4=40+4=44\r
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\n" ); document.write( "\n" ); document.write( "Answer: width is 20 and length is 44
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