document.write( "Question 290628: Find the vertex of the parabola:
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Algebra.Com's Answer #210296 by user_dude2008(1862)\"\" \"About 
You can put this solution on YOUR website!
y=-x^2+(1/2)x+2\r
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\n" ); document.write( "\n" ); document.write( "y=-(x^2-(1/2)x-2)\r
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\n" ); document.write( "\n" ); document.write( "y=-(x^2-(1/2)x+1/16-1/16-2)\r
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\n" ); document.write( "\n" ); document.write( "y=-((x-1/4)^2-1/16-2)\r
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\n" ); document.write( "\n" ); document.write( "y=-((x-1/4)^2-33/16)\r
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\n" ); document.write( "\n" ); document.write( "y=-(x-1/4)^2+33/16\r
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\n" ); document.write( "\n" ); document.write( "Vertex is (1/4, 33/16)
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