document.write( "Question 290557: The length of a swimming pool is to be three times the width. If the depth is to be a constant 4 feet and the volume is to be 4800 cubic feet, find the length and width. \n" ); document.write( "
Algebra.Com's Answer #210271 by checkley77(12844)\"\" \"About 
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L=3W
\n" ); document.write( "V=LWD
\n" ); document.write( "4800=3W*W*4
\n" ); document.write( "4800=12W^2
\n" ); document.write( "W^2=4800/12
\n" ); document.write( "W^2=2400
\n" ); document.write( "W^2=400
\n" ); document.write( "W=SQRT400
\n" ); document.write( "W=20 FT. ANS. FOR THE WIDTH.
\n" ); document.write( "L=3*20=60 FT. ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "4800=60*20*4
\n" ); document.write( "4800=4800
\n" ); document.write( "
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