document.write( "Question 290557: The length of a swimming pool is to be three times the width. If the depth is to be a constant 4 feet and the volume is to be 4800 cubic feet, find the length and width. \n" ); document.write( "
Algebra.Com's Answer #210271 by checkley77(12844) ![]() You can put this solution on YOUR website! L=3W \n" ); document.write( "V=LWD \n" ); document.write( "4800=3W*W*4 \n" ); document.write( "4800=12W^2 \n" ); document.write( "W^2=4800/12 \n" ); document.write( "W^2=2400 \n" ); document.write( "W^2=400 \n" ); document.write( "W=SQRT400 \n" ); document.write( "W=20 FT. ANS. FOR THE WIDTH. \n" ); document.write( "L=3*20=60 FT. ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "4800=60*20*4 \n" ); document.write( "4800=4800 \n" ); document.write( " |