document.write( "Question 290564: The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the legnth and width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "I think the equation is
\n" ); document.write( "(L-4) * L = 96 CM ^2
\n" ); document.write( "L^2 - 4L=96 \r
\n" ); document.write( "\n" ); document.write( "How do I get rid of the 4L? So I can take the square root of the number on the right? Is the second step of the formula correct?my formalus
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #210254 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the length and width of the rectangle.
\n" ); document.write( "I think the equation is
\n" ); document.write( "(L-4) * L = 96 CM ^2
\n" ); document.write( "L^2 - 4L=96
\n" ); document.write( "How do I get rid of the 4L?
\n" ); document.write( "Subtract 96 from both sides:
\n" ); document.write( "L^2-4L-96 = 0
\n" ); document.write( "(L+8)(L-12) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "Length = 12 cm
\n" ); document.write( "Width = L-4 = 8 cm
\n" ); document.write( "=======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "So I can take the square root of the number on the right? Is the second step of the formula correct?my formalus
\n" ); document.write( "-------------------\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );