document.write( "Question 290422: a chemist has 6 liters of a 50% acid solution. how much water must be added to obtain a 20% acid solution ? \n" ); document.write( "
Algebra.Com's Answer #210160 by stanbon(75887)\"\" \"About 
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a chemist has 6 liters of a 50% acid solution. how much water must be added to obtain a 20% acid solution ?
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.50*3 + 0*x = 0.20(3+x)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50*3 + 0 = 20*3 + 20x
\n" ); document.write( "20x = 30*3
\n" ); document.write( "x = (3/2)3
\n" ); document.write( "x = 4.5 liters (amount of water needed for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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