document.write( "Question 290422: a chemist has 6 liters of a 50% acid solution. how much water must be added to obtain a 20% acid solution ? \n" ); document.write( "
Algebra.Com's Answer #210160 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a chemist has 6 liters of a 50% acid solution. how much water must be added to obtain a 20% acid solution ? \n" ); document.write( "------------------------------------ \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.50*3 + 0*x = 0.20(3+x) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50*3 + 0 = 20*3 + 20x \n" ); document.write( "20x = 30*3 \n" ); document.write( "x = (3/2)3 \n" ); document.write( "x = 4.5 liters (amount of water needed for the mixture) \n" ); document.write( "=========================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================================== \n" ); document.write( " |