document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34753>Question 34753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify<BR>\n" );
document.write( "1/3[2ln(x+3) + lnx - ln(x2-1)]\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21014 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3[2ln(x+3) + lnx - ln(x^2-1)]<BR>\n" );
document.write( "= 1/3 [ln(x+3)^2 + lnx - ln(x^2-1)]<BR>\n" );
document.write( "= 1/3 ln[x(x+3)^2/(x^2-1]<BR>\n" );
document.write( "= ln[x(x+3)^2/(x^2-1]^1/3<BR>\n" );
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