document.write( "Question 290282: Three times the sum of three consecutive intergers is equal to the produsct of the two smallest integers. \n" ); document.write( "
Algebra.Com's Answer #210070 by richwmiller(17219)\"\" \"About 
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3*(n+n+1+n+2)=n*(n+1)
\n" ); document.write( "3*(3n+3)=n^2+n
\n" ); document.write( "9n+9=n^2+n
\n" ); document.write( "n=-1 and n=9
\n" ); document.write( "-1,0,1
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\n" ); document.write( "0=0
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\n" ); document.write( "\n" ); document.write( "9,10,11
\n" ); document.write( "check
\n" ); document.write( "3*(30)=9*10
\n" ); document.write( "90=90\r
\n" ); document.write( "\n" ); document.write( "so there are two sets of answers
\n" ); document.write( "-1,0,1
\n" ); document.write( "and 9,10,11
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