document.write( "Question 290282: Three times the sum of three consecutive intergers is equal to the produsct of the two smallest integers. \n" ); document.write( "
Algebra.Com's Answer #210070 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 3*(n+n+1+n+2)=n*(n+1) \n" ); document.write( "3*(3n+3)=n^2+n \n" ); document.write( "9n+9=n^2+n \n" ); document.write( "n=-1 and n=9 \n" ); document.write( "-1,0,1 \n" ); document.write( "check \n" ); document.write( "0=0 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( "9,10,11 \n" ); document.write( "check \n" ); document.write( "3*(30)=9*10 \n" ); document.write( "90=90\r \n" ); document.write( "\n" ); document.write( "so there are two sets of answers \n" ); document.write( "-1,0,1 \n" ); document.write( "and 9,10,11 \n" ); document.write( " \n" ); document.write( " |