document.write( "Question 290274: Please disregard my previous problem I wrote it wrong.\r
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\n" ); document.write( "\n" ); document.write( "0.5x^2=x+0.5
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Algebra.Com's Answer #210047 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"0.5x%5E2=x%2B0.5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=2x%2B1\" Multiply EVERY term by 2 (note: \"0.5=1%2F2\") to clear out the decimals.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-1=0\" Get every term to the left side.\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"x%5E2-2%2Ax-1=0\" ( notice \"a=1\", \"b=-2\", and \"c=-1\")
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\n" ); document.write( " \"x+=+%28--2+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A-1+%29%29%2F%282%2A1%29\" Plug in a=1, b=-2, and c=-1
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A-1+%29%29%2F%282%2A1%29\" Negate -2 to get 2
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+4-4%2A1%2A-1+%29%29%2F%282%2A1%29\" Square -2 to get 4 (note: remember when you square -2, you must square the negative as well. This is because \"%28-2%29%5E2=-2%2A-2=4\".)
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+4%2B4+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-1%2A1\" to get \"4\"
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+8+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%282+%2B-+2%2Asqrt%282%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%282+%2B-+2%2Asqrt%282%29%29%2F2\" Multiply 2 and 1 to get 2
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%282+%2B+2%2Asqrt%282%29%29%2F2\" or \"x+=+%282+-+2%2Asqrt%282%29%29%2F2\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"x=%2B2%2F2%2B2%2Asqrt%282%29%2F2\" or \"x=%2B2%2F2-2%2Asqrt%282%29%2F2\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"x=1%2Bsqrt%282%29\" or \"x=1-sqrt%282%29\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"x=1%2Bsqrt%282%29\" or \"x=1-sqrt%282%29\"
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=1%2Bsqrt%282%29\" or \"x=1-sqrt%282%29\"
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