document.write( "Question 290237: Square root 2y+1=5\r
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Algebra.Com's Answer #210032 by checkley77(12844)\"\" \"About 
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sqrt(2y+1)=5
\n" ); document.write( "square both sides.
\n" ); document.write( "4y^2+4y+1=25
\n" ); document.write( "4y^2+4y+1-25=0
\n" ); document.write( "4y^2+4y-24=0
\n" ); document.write( "4(y^2+y-6)=0
\n" ); document.write( "4(y+3)(y-2)=0
\n" ); document.write( "y+3=0
\n" ); document.write( "y=-3 ans
\n" ); document.write( "y-2=0
\n" ); document.write( "y=2 ans.
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