document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=290140>Question 290140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle measures 40 degrees more than the measure of a complementary angle.what is the measure of the  greater angle?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209971 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the two complimentary angles is 90 deg\r<BR>\n" );
document.write( "\n" );
document.write( "let the angle be x\r<BR>\n" );
document.write( "\n" );
document.write( "The other angle will be x+40\r<BR>\n" );
document.write( "\n" );
document.write( "x+x+40 = 90\r<BR>\n" );
document.write( "\n" );
document.write( "2x+40=90\r<BR>\n" );
document.write( "\n" );
document.write( "2x=90-40\r<BR>\n" );
document.write( "\n" );
document.write( "2x=50\r<BR>\n" );
document.write( "\n" );
document.write( "x=50/2<BR>\n" );
document.write( "x=25\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the bigger angle is greater by 40 deg.\r<BR>\n" );
document.write( "\n" );
document.write( "25+40 = 65 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );