document.write( "Question 290114: How do I solve for: \r
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document.write( "a) 5 + sqrt. x = 15\r
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document.write( "b) 2 sqrt. x + 1 = sqrt. x - 5 \n" );
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Algebra.Com's Answer #209967 by alegriajoy33(14)![]() ![]() You can put this solution on YOUR website! Okay \n" ); document.write( "5+sqrtx =15 \n" ); document.write( "subtract 5 \n" ); document.write( "so you get \n" ); document.write( "sqrtx=15 \n" ); document.write( "now square both sides you get \n" ); document.write( "x=225\r \n" ); document.write( "\n" ); document.write( "I am not sure what b is so I am going to do what I think it is. \n" ); document.write( "2*sqrt(x+1)= sqrt (x-5) \n" ); document.write( "first thing square bot sides. \n" ); document.write( "you get \n" ); document.write( "4*(x+1)=x-5 distribute \n" ); document.write( "4x+4=x-5 subtract x \n" ); document.write( "3x+4=-5 add 5 \n" ); document.write( "3x+9=0 subtract 9 \n" ); document.write( "3x=-9 divide by 3 \n" ); document.write( "x=-3 answer \n" ); document.write( "I hope I did this one right I know the first one is right the second I am not quite possitive on but I am pretty sure itis right. \n" ); document.write( " |