document.write( "Question 290114: How do I solve for: \r
\n" ); document.write( "\n" ); document.write( "a) 5 + sqrt. x = 15\r
\n" ); document.write( "\n" ); document.write( "b) 2 sqrt. x + 1 = sqrt. x - 5
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Algebra.Com's Answer #209967 by alegriajoy33(14)\"\" \"About 
You can put this solution on YOUR website!
Okay
\n" ); document.write( "5+sqrtx =15
\n" ); document.write( "subtract 5
\n" ); document.write( "so you get
\n" ); document.write( "sqrtx=15
\n" ); document.write( "now square both sides you get
\n" ); document.write( "x=225\r
\n" ); document.write( "\n" ); document.write( "I am not sure what b is so I am going to do what I think it is.
\n" ); document.write( "2*sqrt(x+1)= sqrt (x-5)
\n" ); document.write( "first thing square bot sides.
\n" ); document.write( "you get
\n" ); document.write( "4*(x+1)=x-5 distribute
\n" ); document.write( "4x+4=x-5 subtract x
\n" ); document.write( "3x+4=-5 add 5
\n" ); document.write( "3x+9=0 subtract 9
\n" ); document.write( "3x=-9 divide by 3
\n" ); document.write( "x=-3 answer
\n" ); document.write( "I hope I did this one right I know the first one is right the second I am not quite possitive on but I am pretty sure itis right.
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