document.write( "Question 290049: Solve for all possible triangles that satisfy a=9, b=13, measure of angle b=67 degrees. Round all values to the nearest tenth.
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document.write( "I know it is a lot of work, so i did part of it already :]
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document.write( "Since you know 2 sides and an angle. I can use law of sine to find a second angle. Since all the interior angles of a triangle is equal to 180 degrees, I can find the third angle. After this, I'm not too sure how to find the possible \"multiple\" types of triangles there are. Please help! Thank-you! \n" );
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Algebra.Com's Answer #209945 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! Solve for all possible triangles that satisfy a=9, b=13, measure of angle b=67 degrees. Round all values to the nearest tenth. \n" ); document.write( "I know it is a lot of work, so i did part of it already :] \n" ); document.write( "Since you know 2 sides and an angle. I can use law of sine to find a second angle. Since all the interior angles of a triangle is equal to 180 degrees, I can find the third angle. After this, I'm not too sure how to find the possible \"multiple\" types of triangles there are. Please help! Thank-you!\r \n" ); document.write( "\n" ); document.write( "You're doing GREAT!. You can find angle \"a\" using the law of sines:\r \n" ); document.write( "\n" ); document.write( "(sin a)/9 = (sin 67)/13\r \n" ); document.write( "\n" ); document.write( "Once you have angle \"a\" (the angle with sin(a) above) then you can find angle \"c\" as you said by subtracting 67 and angle \"a\" from 180.\r \n" ); document.write( "\n" ); document.write( "Now that you have angle \"c\" you can find side \"c\" by:\r \n" ); document.write( "\n" ); document.write( "(sin 67)/13 = (sin c)/c \r \n" ); document.write( "\n" ); document.write( "Now you have all three sides and all three angles. Based on the side-side-side congruence theorem this defines a unique triangle. \n" ); document.write( " |