document.write( "Question 290001: A barge travels 63 miles upriver and 63 miles downriver in a toal time of 15 hours. the speed of the current is 4 mph. Find the speed of the barge in still water. \n" ); document.write( "
Algebra.Com's Answer #209925 by Fombitz(32388)\"\" \"About 
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Rate*Time=Distance
\n" ); document.write( "Let's call the speed of the barge S.
\n" ); document.write( "Against the current,
\n" ); document.write( "1.\"%28S-4%29%2AT1=63\"
\n" ); document.write( "With the current,
\n" ); document.write( "2.\"%28S%2B4%29%2AT2=63\"
\n" ); document.write( "and we also know
\n" ); document.write( "\"T1%2BT2=15\"
\n" ); document.write( "From eq. 1 and 2,
\n" ); document.write( "\"T1=63%2F%28S-4%29\"
\n" ); document.write( "\"T2=63%2F%28S%2B4%29\"
\n" ); document.write( "Then,
\n" ); document.write( "\"63%2F%28S-4%29%2B63%2F%28S%2B4%29=15\"
\n" ); document.write( "\"63%28S%2B4%29%2B63%28S-4%29=15%28S%2B4%29%28S-4%29\"
\n" ); document.write( "\"63S%2B252%2B63S-252=15%28S%5E2-4S%2B4S-16%29\"
\n" ); document.write( "\"126S=15S%5E2-240\"
\n" ); document.write( "\"15S%5E2-126S-240=0\"
\n" ); document.write( "\"5S%5E2-42S-80=0\"
\n" ); document.write( "You can factor this equation.
\n" ); document.write( "\"%285S%2B8%29%28S-10%29=0\"
\n" ); document.write( "Two solutions,
\n" ); document.write( "\"5S%2B8=0\"
\n" ); document.write( "\"5S=-8\"
\n" ); document.write( "\"S=-8%2F5\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"S-10=0\"
\n" ); document.write( "\"S=10\"
\n" ); document.write( "Since we specified the direction of with and against the current, we assumed the barge speed was positive, so we only keep the positive result.
\n" ); document.write( "\"highlight%28S=10%29\"
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