document.write( "Question 289942: 4x-3y=10
\n" ); document.write( "2x-3y=2
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Algebra.Com's Answer #209891 by brucewill(101)\"\" \"About 
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4x - 3y = 10
\n" ); document.write( "2x - 3y = 2\r
\n" ); document.write( "\n" ); document.write( "Subtract the second statement from the first:\r
\n" ); document.write( "\n" ); document.write( "2x = 8
\n" ); document.write( "\"highlight%28x+=+4%29\"\r
\n" ); document.write( "\n" ); document.write( "Substitute for x back into either statment (I choose the first):\r
\n" ); document.write( "\n" ); document.write( "4(4) - 3y = 10
\n" ); document.write( "16 - 3y = 10
\n" ); document.write( "-3y = -6
\n" ); document.write( "\"highlight%28y+=+2%29\"\r
\n" ); document.write( "\n" ); document.write( "Prove: (substitute back into both equations:
\n" ); document.write( "4(4) - (3)(2) = 10
\n" ); document.write( "16 - 6 = 10
\n" ); document.write( "10 = 10. OK\r
\n" ); document.write( "\n" ); document.write( "2(4) - 3(2) = 2
\n" ); document.write( "8 - 6 = 2. OK.
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