document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34723>Question 34723</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321227573/algebrahomeworkh>College algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I need help. I don't know where to go from here. Okay, questions is; write and equations(a) in standard form and (b) in slope-intercept form.<BR>\n" );
document.write( "Problem; through -(2, 0), Perpendicular to 8x-3y=7<BR>\n" );
document.write( "This is what I came with and I don't know what to do after, if I even got this much right? y-0=3/8 (x-(-2), Y-0=3/8x+6/8...Thank you for your help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20987 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> straight line will take the form y=mx+c. We needs its gradient (m) and y-intercept (c).\r<BR>\n" );
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document.write( "Perpendicular to 8x-3y=7. OK, so first we need to write this like y=mx+c so we know its gradient...\r<BR>\n" );
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document.write( "8x-3y=7<BR>\n" );
document.write( "8x-7 = 3y<BR>\n" );
document.write( "or 3y = 8x-7<BR>\n" );
document.write( "y = (8/3)x-7/3\r<BR>\n" );
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document.write( "Its gradient is 8/3. Our needed line, being perpendicular to this, will therefore have a gradient of -(3/8)... How do i know? invert the given gradient and change sign, basically to find the perpendicular one..eg for gradient of 3, perpendicular gradient is -1/3.\r<BR>\n" );
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document.write( "So, we have y=-(3/8)x + c. Now for c. Well we need to know a x and y pair, which we do: (2,0) or is it (-2,0)? I am picking the first. If the latter, then you will have to correct my working from here in.\r<BR>\n" );
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document.write( "0=-(3/8)(2) + c<BR>\n" );
document.write( "0=-(6/8) + c<BR>\n" );
document.write( "c = 6/8\r<BR>\n" );
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document.write( "--> equation is y=-(3/8)x + 6/8<BR>\n" );
document.write( "This is slope/intercept form.\r<BR>\n" );
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document.write( "As for \"standard form\" i am not sure what your syllabus calls this, so i shall just write it with no fractions and no negatives:<BR>\n" );
document.write( "y=-(3/8)x + 6/8<BR>\n" );
document.write( "8y=-3x + 6<BR>\n" );
document.write( "8y+3x = 6\r<BR>\n" );
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document.write( "Hopefully this is what you mean by standard form?\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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