document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34716>Question 34716</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780618313850/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex, focus, and directrix of the parabola and graph it.\r<BR>\n" );
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document.write( "x^2-2x+8y+9=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20979 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING AND TRY<BR>\n" );
document.write( "Quadratic-relations-and-conic-sections/33190: 6. What is the directrix of the parabola with the equation y+3=(1/10) (x+2)^2 ?<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 19633 by venugopalramana(1377) About Me  on 2006-04-11 00:48:42 (Show Source):<BR>\n" );
document.write( "y+3=(1/10) (x+2)^2<BR>\n" );
document.write( "STANDARD EQN.OF PARABOLA IS<BR>\n" );
document.write( "(X-H)^2=4A(Y-K)...WHERE<BR>\n" );
document.write( "FOCUS IS (H,K+A)<BR>\n" );
document.write( "DIRECTRIX IS Y-K+A=0<BR>\n" );
document.write( "AXIS IS X-H=0<BR>\n" );
document.write( "VERTEX IS (H,K)<BR>\n" );
document.write( "HERE WE HAVE<BR>\n" );
document.write( "(X+2)^2=10(Y+3)...SO COMPARING WE GET<BR>\n" );
document.write( "H=-2.....K=-3.....4A=10...OR...A=2.5...HENCE<BR>\n" );
document.write( "DIRECTRIX IS GIVEN BY<BR>\n" );
document.write( "Y-K+A=0....OR.....<BR>\n" );
document.write( "Y-(-3)+2.5=0<BR>\n" );
document.write( "Y+3+2.5=0<BR>\n" );
document.write( "Y+5.5=0<BR>\n" );
document.write( "2Y+11=0\r<BR>\n" );
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document.write( "Linear_Algebra/30362: Question: Find the equation of the ellipse whose center is (5,-3) that has a vertex at 13,-3) and a minor axis of lenght 10.<BR>\n" );
document.write( "POssible Answers:<BR>\n" );
document.write( "(A) (x-5)^2/64 + (y+3)^2/25 = 1<BR>\n" );
document.write( "(B) (x+5)^2/64 + (y-3)^2/25 = 1<BR>\n" );
document.write( "(C) x^2/64 + y^2/25 = 1<BR>\n" );
document.write( "(D) none of these<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 17014 by venugopalramana(1167) About Me  on 2006-03-15 11:21:03 (Show Source):<BR>\n" );
document.write( "SEE THE FOLLOWING AND TRY..IF STILL IN DIFFICULTY PLEASE COME BACK...<BR>\n" );
document.write( "OK I WORKED IT OUT FOR YOU NOW<BR>\n" );
document.write( "I TOLD YOU EQN IS<BR>\n" );
document.write( "(X-H)^2/A^2 + (Y-K)^2/B^2....<BR>\n" );
document.write( "WHERE H,K IS CENTRE...SO H=5 AND K=-3 AS CENTRE IS GIVEN AS (5,-3)....NOW VERTEX IS (13,-3)...IT LIES ON ELLIPSE..SO IT SATISFIES THE EQN<BR>\n" );
document.write( "(13-5)^2/A^2 +(-3+3)^2/B^2 =1<BR>\n" );
document.write( "HENCE A^2=64...OR A=8<BR>\n" );
document.write( "MINOR AXIS =10=2B...HENCE B=5..SO EQN.S<BR>\n" );
document.write( "(X-H)^2/64 + (Y+3)^2/25 =1<BR>\n" );
document.write( "THAT IS A IS CORRECT. </SPAN>\n" );
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