document.write( "Question 34664: the function f(x)= x/3-x find an expression for (f to the negative 1 power) f-1 (x) in addition state the domain of both f and f (-1) \n" ); document.write( "
Algebra.Com's Answer #20978 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+f%28x%29=+x%2F%283-x%29+\" --> its domain is any real value of x but not x=3. This is because when x=3, the denominator is then zero and any fraction having a zero denominator gives \"ERROR\" on your calculator, so HAS TO BE avoided.\r
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\n" ); document.write( "\n" ); document.write( "Inverse:
\n" ); document.write( "\"+y+=+x%2F%283-x%29+\"
\n" ); document.write( "\"+y%283-x%29+=+x+\"
\n" ); document.write( "\"+3y-xy+=+x+\"
\n" ); document.write( "\"+3y-xy-x+=+0+\"
\n" ); document.write( "\"+-xy-x+=+-3y+\"
\n" ); document.write( "\"+-x%28y%2B1%29+=+-3y+\"
\n" ); document.write( "\"+x%28y%2B1%29+=+3y+\"
\n" ); document.write( "\"+x+=+%283y%29%2F%28y%2B1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "so, here we have \"+f%28y%29+=+%283y%29%2F%28y%2B1%29+\", or seeing as how we usually quote equations in terms of x: \"+f%28x%29+=+%283x%29%2F%28x%2B1%29+\". And as this is the inverse function of the original, then we can say: \"+f%5E%28-1%29%28x%29+=+%283x%29%2F%28x%2B1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Its domain is: any real value of x but not x=-1 for exactly the same reason as before.\r
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