document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289652>Question 289652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Pu%5E230 ALIGN=MIDDLE  ALT=\"Pu%5E230\"   DISABLED_style= \"max-width:90%; height:auto;\" > is 1620 years. If 2.1 grams remian after 1000 years, whay is the initial quantity anf how much will remain after 10000 years?\r<BR>\n" );
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document.write( "I am using the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=Pe%5Ert ALIGN=MIDDLE  ALT=\"A=Pe%5Ert\"   DISABLED_style= \"max-width:90%; height:auto;\" > formula and so far have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.1=Pe%5E%2824360+X+1000%29 ALIGN=MIDDLE  ALT=\"2.1=Pe%5E%2824360+X+1000%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, have I set this up right? If so, where do I go from here?\r<BR>\n" );
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document.write( "Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209746 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The half-life of Pu 230 is 1620 years. <BR>\n" );
document.write( "If 2.1 grams remain after 1000 years, what is the initial quantity?<BR>\n" );
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document.write( "The half life equation is: A = Ao*2^(-t/h)<BR>\n" );
document.write( "where<BR>\n" );
document.write( "A = the resulting amt after t years<BR>\n" );
document.write( "Ao = initial amt (t=0)<BR>\n" );
document.write( "t = time in yrs<BR>\n" );
document.write( "h = half-life of the substance<BR>\n" );
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document.write( "Find the initial qty<BR>\n" );
document.write( "Ao*2^(-1000/1620) = 2.1<BR>\n" );
document.write( "Ao*2^-.617284<BR>\n" );
document.write( "Using a calc: enter 2^-.617284 and you have:<BR>\n" );
document.write( ".6519Ao = 2.1<BR>\n" );
document.write( "Ao = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.1%2F.6519 ALIGN=MIDDLE  ALT=\"2.1%2F.6519\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Ao = 3.22 grams is the initial qty<BR>\n" );
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document.write( "Check on a calc: enter 3.22*2^(-1000/1620) = 2.099 ~ 2.1, confirms our solution<BR>\n" );
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document.write( "how much will remain after 10000 years?<BR>\n" );
document.write( "Using Ao = 3.22, find A<BR>\n" );
document.write( "A = 3.22*2^(-10000/1620)<BR>\n" );
document.write( "using a calc<BR>\n" );
document.write( "A = .044 grams after 10,000 years </SPAN>\n" );
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