document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289656>Question 289656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 units less than twice the width.  If the length is decreased by 3 units and the width is increased by 1 unit, the area is decreased by 16 square units.  If w is the original width, which equation must be true?<BR>\n" );
document.write( "A.  (2w-3)(w-3)=w(2w-4)-16<BR>\n" );
document.write( "B.  2(2w-3)+2(w-3)=2w+2(2w-4)-16<BR>\n" );
document.write( "C.  (2w-7)(w+1)=w(2w-4)-16<BR>\n" );
document.write( "D.  2(2w-7)+2(w+1)=2w+(2w-4)-16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209739 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l=-4+2w<BR>\n" );
document.write( "l=2w-4<BR>\n" );
document.write( "new l ((2w-4)-3)<BR>\n" );
document.write( "new (w+1)\r<BR>\n" );
document.write( "\n" );
document.write( " ((2w-4)-3)*(w+1)=(2w-4)*(w)-16<BR>\n" );
document.write( " (2w-7)*(w+1)=(2w-4)*(w)-16<BR>\n" );
document.write( "C. answer<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );