document.write( "Question 289589: One positive integer is 3 less than a second positive integer. The sum of the squares of the two integers is 65. Find both positive integers. \n" ); document.write( "
Algebra.Com's Answer #209717 by ankor@dixie-net.com(22740)\"\" \"About 
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One positive integer is 3 less than a second positive integer.
\n" ); document.write( "x = an integer
\n" ); document.write( "(x+3) = 2nd integer
\n" ); document.write( ":
\n" ); document.write( " The sum of the squares of the two integers is 65. Find both positive integers.
\n" ); document.write( "x^2 + (x+3)^2 = 65
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + x^2 + 6x + 9 = 65
\n" ); document.write( ":
\n" ); document.write( "2x^2 + 6x + 9 - 65 = 0
\n" ); document.write( ":
\n" ); document.write( "2x^2 + 6x - 56 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(2x + 14)(x - 4) - 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = 4 is the 1st integer
\n" ); document.write( "and
\n" ); document.write( "4 + 3 = 7 is the 2nd integer
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\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( "4^2 + 7^2 = 65 \n" ); document.write( "
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