document.write( "Question 4567: We are required to form different words with the help of letters of the word 'INTEGER'.
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document.write( "let m1 be the number of words in which 'I' and 'N' are never together and m2 be the number of words which begin with 'I 'and end with 'R',
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document.write( "then m1/m2 is given by ? \n" );
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Algebra.Com's Answer #2097 by khwang(438)![]() ![]() ![]() You can put this solution on YOUR website! All possible words: 7!/2! = 7*6!/2 (since there are 2 E's) \n" ); document.write( " If TN together TN or NT as a letter, the other five are EE,I,G,R \n" ); document.write( " so there are 2*6!/2! = 6! = 720\r \n" ); document.write( "\n" ); document.write( " Hence,m1 = 7*6!/2 - 720 = 720(7/2 -1) = 720 (5/2) = 1800 \n" ); document.write( " \n" ); document.write( " m2 = 5!/2 = 60 (why?)\r \n" ); document.write( "\n" ); document.write( " So, m1/m2 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Kenny \n" ); document.write( " |