document.write( "Question 289559: I am trying to solve log(x-1)+log(x+2)=1, I have the answer, which is 3, but am looking to see the problem worked. I appreciate the help. Thank you.\r
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Algebra.Com's Answer #209678 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Note: All logs are assumed to be base 10.\r
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\n" ); document.write( "\n" ); document.write( "Hint: Use the idea that $\"log%28%28x%29%29%2Blog%28%28y%29%29=log%28%28xy%29%29\"$ to get $\"log%28%28%28x-1%29%28x%2B2%29%29%29=1\"$ . Now convert into exponential form to get $\"%28x-1%29%28x%2B2%29=10%5E1\"$ and simplify to get $\"%28x-1%29%28x%2B2%29=10\"$ . I'll let you take it from here. \n" ); document.write( "

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