document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289258>Question 289258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 70=19-3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209650 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The goal in any algebra problem such as this is to get x on one side, and all the numbers on the other side.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "70=19-3x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "First, let's subtract 19 from both sides:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "70-19=-3x<BR>\n" );
document.write( "51=-3x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Next, we need to divide both sides of the equation by -3:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "51/(-3) = x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = -17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );