document.write( "Question 34711: The problem is a word problem it goes like this...\r
\n" ); document.write( "\n" ); document.write( "You invest 2,000 dollars at an annual interest rate of 5% for 3 years.
\n" ); document.write( "Find the amount for each account...\r
\n" ); document.write( "\n" ); document.write( "Compounded daily = ?\r
\n" ); document.write( "\n" ); document.write( "Compounded monthly = ?\r
\n" ); document.write( "\n" ); document.write( "Compounded continuously = ?\r
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Algebra.Com's Answer #20965 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Value = (amount at the beginning)(1+r/n)^(nt)
\n" ); document.write( "r is the yearly rate of interest
\n" ); document.write( "n is the number of times in a year the money is compounded
\n" ); document.write( "t is the number of years this compounding goes on\r
\n" ); document.write( "\n" ); document.write( "A=2000(1+0.05/365)^(365*3)
\n" ); document.write( "A=2000(1.000136986...)^1095
\n" ); document.write( "A=$2323.64 (value after 3 yrs. compounded daily at 5% per annum)\r
\n" ); document.write( "\n" ); document.write( "I'll let you do the monthly where n=12\r
\n" ); document.write( "\n" ); document.write( "For \"continuous\" compounding the formula changes to:
\n" ); document.write( "V = Amount* e^(rt)
\n" ); document.write( "V = 2000 e^(0.05*3)
\n" ); document.write( "V= 2000(1.161834...
\n" ); document.write( "v=$2323.67
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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