document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289429>Question 289429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a car leaves town and drives east at 50 miles per hour. a second car leaves the same point three hours later and also drives north at 50 miles per hour. how far apart are they 4 hours after the second care leaves? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209630 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first car went 3*50=150 miles before the second car left<BR>\n" );
document.write( "after 4 more hours they each go 200 miles.<BR>\n" );
document.write( "So the first car has gone 350 and the second car 200<BR>\n" );
document.write( "the distance between them d=sqrt(350^2+200^2)=50sqrt(65)=403.11 </SPAN>\n" );
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