document.write( "Question 289398: Find \"+sin2x+\" if \"+secx=-4+\" and \"+sinx%3C0+\" \n" ); document.write( "
Algebra.Com's Answer #209617 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
Find \"+sin2x+\" if \"+secx=-4+\" and \"+sinx%3C0+\"\r
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document.write( "Since the secant and the sine of x are both negative, that means\r\n" );
document.write( "x is in the third quadrant. between 180° and 270° in degress,\r\n" );
document.write( "or between \"pi\" and \"3pi%2F2\" in radians.  So therefore\r\n" );
document.write( "2x will be between 360° and 540° which is actually the 1st and\r\n" );
document.write( "2nd quadrants.  The sine is positive in both the 1st and 2nd\r\n" );
document.write( "quadrants, so the answer will be posotive.\r\n" );
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document.write( "We need these identities:\r\n" );
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document.write( "1. \"Sin%282theta%29+=+2Sin%28theta%29Cos%28theta%29\"\r\n" );
document.write( "2. \"Cos%5E2theta+%2B+Sin%5E2theta=1\" \r\n" );
document.write( "3. \"Cos%28theta%29=1%2FSec%28theta%29\" \r\n" );
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document.write( "First we'll find \"Cos%28x%29\" using 3.\r\n" );
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document.write( "\"Cos%28x%29=1%2FSec%28x%29=1%2F%28-4%29=-1%2F4\"\r\n" );
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document.write( "Next we'll find \"Sin%28x%29\" using 2.\r\n" );
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document.write( "\"Cos%5E2x+%2B+Sin%5E2x=1\"\r\n" );
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document.write( "\"%28-1%2F4%29%5E2%2BSin%5E2x=1\"\r\n" );
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document.write( "\"1%2F16%2BSin%5E2x=1\"\r\n" );
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document.write( "\"Sin%5E2x=1-1%2F16\"\r\n" );
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document.write( "\"Sin%5E2x=16%2F16-1%2F16\"\r\n" );
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document.write( "\"Sin%5E2x=15%2F16\"\r\n" );
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document.write( "\"Sin%28x%29=%22%22%2B-sqrt%2815%2F16%29=%22%22%2B-sqrt%2815%29%2F4\"\r\n" );
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document.write( "However, since \"Sin%28x%29%3C0\" we take the negative sign,\r\n" );
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document.write( "\"Sin%28x%29=-sqrt%2815%29%2F4\"\r\n" );
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document.write( "Now we can substitute in 1:\r\n" );
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document.write( "\"Sin%282x%29+=+2Sin%28x%29Cos%28x%29\"\r\n" );
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document.write( "\"Sin%282x%29+=+2%28-sqrt%2815%29%2F4%29%28-1%2F4%29\"\r\n" );
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document.write( "\"Sin%282x%29+=+2sqrt%2815%29%2F16%29\"\r\n" );
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document.write( "\"Sin%282x%29+=+sqrt%2815%29%2F8\"\r\n" );
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document.write( "Edwin

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