document.write( "Question 289408: Judy has three more dimes than nickels and twice as many nickels as quarters. If altogether she has 85 cents in nickels, dimes, and quarters, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #209614 by stanbon(75887)\"\" \"About 
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Judy has three more dimes than nickels and twice as many nickels as quarters. If altogether she has 85 cents in nickels, dimes, and quarters, how many of each coin does she have?
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\n" ); document.write( "Equations:
\n" ); document.write( "d = n+3
\n" ); document.write( "n = 2q
\n" ); document.write( "5n + 10d + 25q = 85 cents
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\n" ); document.write( "Substitute and solve for \"n\"
\n" ); document.write( "5n + 10(n+3) + 25(n/2) = 85
\n" ); document.write( "Multiply thru by 2 to get:
\n" ); document.write( "10n + 20n + 60 + 25n = 170
\n" ); document.write( "55n = 110
\n" ); document.write( "n = 2 (# of nickels)
\n" ); document.write( "d = n+3 = 5 (# of dimes)
\n" ); document.write( "q = (1/2)n = 1 (# of quarters)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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