document.write( "Question 289308: Hi I couldnt figure out how to do this problem\r
\n" ); document.write( "\n" ); document.write( "LOG6(x+3)+LOG6(x-2)=1
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Algebra.Com's Answer #209587 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Hi I couldnt figure out how to do this problem
\n" ); document.write( "LOG6(x+3)+LOG6(x-2)=1
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\n" ); document.write( "log6[(x+3)(x-2)] = 1
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\n" ); document.write( "x^2+x-6 = 6^1
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\n" ); document.write( "x^2+x-12 = 0
\n" ); document.write( "(x-4)(x+3) = 0
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\n" ); document.write( "Acceptable solution:
\n" ); document.write( "x = 4
\n" ); document.write( "Note: x cannot be -3 because log(x-3)
\n" ); document.write( "would be log(0) which does not exist.\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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