document.write( "Question 289114: Sheila invested $50,000 in two accounts last year. One account earned 6% and the other earned 7% annual interest. If the total income last year from these investments was $3350, how much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #209566 by checkley77(12844) ![]() You can put this solution on YOUR website! .07x+.06(50,000-x)=3,350 \n" ); document.write( ".07x+3,000-.06x=3,350 \n" ); document.write( ".01x=3,350-3,000=0 \n" ); document.write( ".01x=350 \n" ); document.write( "x=350/.01 \n" ); document.write( "x=35,000 ans. for the 7% investment. \n" ); document.write( "50,000-35,000=15,000 ans. for the 6% investment. \n" ); document.write( "Proof: \n" ); document.write( ".07*35,000+.06*15,000=3,350 \n" ); document.write( "2,450+900=3,350 \n" ); document.write( "3,350=3,350 \n" ); document.write( " |