document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289187>Question 289187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the slope of a line that is perpendicular to the graph of: y=(-1/2)x+4? (Please explain). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209545 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=(-1/2)x+4 (red line)<BR>\n" );
document.write( "This line has a slope=-1/2.<BR>\n" );
document.write( "Any perpendicular line will have a slope=the negative reciprocal of -1/2 OR 2.<BR>\n" );
document.write( "y=2x+4 (green line)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%2F2+%2B4%2C+2x+%2B4%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%2F2+%2B4%2C+2x+%2B4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -x/2 +4 and 2x +4).  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );