document.write( "Question 289180: How do I solve this problem? 2/3 - (1/2 - 1/3)
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document.write( "I know I have to find the lcd, but how does the numerator change? \n" );
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Algebra.Com's Answer #209526 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 1/2=1.5/3 \n" ); document.write( "2/3-(1.5/3-1/3) \n" ); document.write( "2/3-(.5/3) \n" ); document.write( "1.5/3=1/2\r \n" ); document.write( "\n" ); document.write( "or even better \n" ); document.write( "2/3-1/2+1/3 \n" ); document.write( "1-1/2=1/2\r \n" ); document.write( "\n" ); document.write( "The normal way would have been \n" ); document.write( "2/3 - (1/2 - 1/3) \n" ); document.write( "convert the denominator to 6 \n" ); document.write( "2/3=4/6 \n" ); document.write( "1/2=3/6 \n" ); document.write( "1/3=2/6\r \n" ); document.write( "\n" ); document.write( "4/6-(3/6-2/6) \n" ); document.write( "4/6-(1/6) \n" ); document.write( "4/6-1/6=3/6=1/2 \n" ); document.write( " \n" ); document.write( " |