document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289131>Question 289131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In testing an engine, various mixtures of gasoline and methanol are being tried. How much of a 90% gasoline mixture and a 75% gasoline mixture are needed for 1200 L of an 85% gasoline mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209500 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much of a 90% gasoline mixture and a 75% gasoline mixture are needed for 1200 L of an 85% gasoline mixture?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "gas + gas = gas<BR>\n" );
document.write( "0.90x + 0.75(1200-x) = 0.85*1200<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Multiply thru by 100 and solve for \"x\":<BR>\n" );
document.write( "90x + 75*1200 - 75x = 85*1200<BR>\n" );
document.write( "15x = 10*1200<BR>\n" );
document.write( "x = (2/3)1200<BR>\n" );
document.write( "x = 800 L (amt. of 90% gasoline needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1200-x = 400 L (amt. of 75% gasoline needed in the mixture)<BR>\n" );
document.write( "====================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );