document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289131>Question 289131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In testing an engine, various mixtures of gasoline and methanol are being tried. How much of a 90% gasoline mixture and a 75% gasoline mixture are needed for 1200 L of an 85% gasoline mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209496 by </B><A HREF=/tutors/aboutme.mpl?userid=brucewill><B>brucewill(101)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=brucewill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = L of 90% gas<BR>\n" );
document.write( "Then (1200 - x) would be the # of L of 75% gas.<BR>\n" );
document.write( "We will end up with 1020L (85% * 1200 L) of overall 100% gas.\r<BR>\n" );
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document.write( ".9x + .75(1200 - x) = 1020<BR>\n" );
document.write( ".9x + 900 - .75x = 1020   <BR>\n" );
document.write( ".15x = 120<BR>\n" );
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document.write( "Prove:<BR>\n" );
document.write( "800 L of 90% gas (720 L pure)<BR>\n" );
document.write( "400 L of 75% gas (300 L pure).<BR>\n" );
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