document.write( "Question 289126: Sqrt(3)+ Sqrt(x-2)=Sqrt(x+3) \n" ); document.write( "
Algebra.Com's Answer #209486 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%283%29%2Bsqrt%28x-2%29=sqrt%28x%2B3%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%283%29%2Bsqrt%28x-2%29%29%5E2=x%2B3\" Square both sides (to eliminate the square root on the right side)\r
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\n" ); document.write( "\n" ); document.write( "\"3%2B2%2Asqrt%283%29%2Asqrt%28x-2%29%2Bx-2=x%2B3\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"3%2B2%2Asqrt%283%28x-2%29%29%2Bx-2=x%2B3\" Combine the roots.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283x-6%29%2Bx%2B1=x%2B3\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283x-6%29=x%2B3-x-1\" Subtract 'x' from both sides. Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283x-6%29=2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%283x-6%29=2%2F2\" Divide both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%283x-6%29=1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-6=1%5E2\" Square both sides (to eliminate the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"3x-6=1\" Square 1 to get 1.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=1%2B6\" Add 6 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=7\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=7%2F3\" Divide both sides by 3 to isolate 'x'.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=7%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "I'll let you do the check. Simply plug this value back into the equation and simplify. You should get an equation that is always true.
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