document.write( "Question 289094: The length of a rectangle is 3 inches more than the width. The area of the rectangle is 154 inches. Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #209483 by jim_thompson5910(35256)\"\" \"About 
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Let L = length and W = width\r
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\n" ); document.write( "\n" ); document.write( "Since \"The length of a rectangle is 3 inches more than the width\", we know that \"L=W%2B3\" (just add 3 to the width to get the length). Furthermore, we're given that \"The area of the rectangle is 154 inches\", so we can say that \"154=LW\" (recall that the area of a rectangle is \"A=LW\", multiply the length and width to get the area).\r
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\n" ); document.write( "\n" ); document.write( "So we have the two equations: \"L=W%2B3\" and \"154=LW\" \r
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\n" ); document.write( "\n" ); document.write( "\"154=LW\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"154=%28W%2B3%29W\" Plug in \"L=W%2B3\". In other words, replace each \"L\" with \"W+3\". Notice how the \"L\" terms are now gone and we now have an equation with one variable.\r
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\n" ); document.write( "\n" ); document.write( "\"154=W%28W%2B3%29\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"154=W%5E2%2B3W\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"0=W%5E2%2B3W-154\" Subtract 154 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28W%2B14%29%28W-11%29\" Factor the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"W%2B14=0\" or \"W-11=0\" Use the zero product property.\r
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\n" ); document.write( "\n" ); document.write( "\"W=-14\" or \"W=11\" Solve for 'W' in each equation.\r
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\n" ); document.write( "\n" ); document.write( "So the two possible solutions for 'W' are \"W=-14\" or \"W=11\". However, since we can't have a negative width, the only solution is \"W=11\".\r
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\n" ); document.write( "\n" ); document.write( "So the width is 11 inches. Now just plug this value into \"L=W%2B3\" to get \"L=W%2B3=11%2B3=14\". So the length is 14 inches.\r
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\n" ); document.write( "\n" ); document.write( "Take note that the length is indeed more than width and that 11*14=154 which verifies our answer.
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