document.write( "Question 289107: a 90% antifreeze solution is to be mixed with a 75% solution to make 30 liters of an 80% solution. How many liters of the 90% and 75% solutions should be used? \n" ); document.write( "
Algebra.Com's Answer #209471 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A 90% antifreeze solution is to be mixed with a 75% solution to make 30 liters of an 80% solution. \n" ); document.write( "How many liters of the 90% and 75% solutions should be used? \n" ); document.write( "----------------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.9x + 0.75(30-x) = 0.30(80) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 and solve for \"x\": \n" ); document.write( "90x + 75*30 - 75x = 30*80 \n" ); document.write( "15x = 5*30 \n" ); document.write( "x = 6 liters (amt. of 90% antifreeze needed in the mixture) \n" ); document.write( "--- \n" ); document.write( "30-x = 24 liters (amt. of 75% antifreeze needed in the mixture) \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================================== \n" ); document.write( " |