document.write( "Question 289107: a 90% antifreeze solution is to be mixed with a 75% solution to make 30 liters of an 80% solution. How many liters of the 90% and 75% solutions should be used? \n" ); document.write( "
Algebra.Com's Answer #209471 by stanbon(75887)\"\" \"About 
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A 90% antifreeze solution is to be mixed with a 75% solution to make 30 liters of an 80% solution.
\n" ); document.write( "How many liters of the 90% and 75% solutions should be used?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.9x + 0.75(30-x) = 0.30(80)
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\n" ); document.write( "Multiply thru by 100 and solve for \"x\":
\n" ); document.write( "90x + 75*30 - 75x = 30*80
\n" ); document.write( "15x = 5*30
\n" ); document.write( "x = 6 liters (amt. of 90% antifreeze needed in the mixture)
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\n" ); document.write( "30-x = 24 liters (amt. of 75% antifreeze needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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