document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289104>Question 289104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square root of 14 over the square root of 3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209468 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(14)/sqrt(3) \r<BR>\n" );
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document.write( "Multiply numerator and denominator by sqrt(3) (same as multiplying by 1):\r<BR>\n" );
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document.write( "(sqrt(14)*Sqrt(3))/(sqrt(3)*sqrt(3)) =<BR>\n" );
document.write( "sqrt(14*3)/sqrt(3^2)=<BR>\n" );
document.write( "sqrt(42)/3 </SPAN>\n" );
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