document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=289019>Question 289019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let f(x)=3x^2-9x+7, for what value of x is the value of the cuntion a minimmum? what is the minimum value? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209393 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Let f(x)=3x^2-9x+7, <BR>\n" );
document.write( "for what value of x is the value of the function a minimum? <BR>\n" );
document.write( "Since the coefficient associated with the x^2 term is +3, we know that it is a parabola that opens downward.  This means the \"axis of symmetry\" will be the minimum.<BR>\n" );
document.write( "x = -b/2a = -(-9)/(2*3) = 9/6 = 3/2 = 1.5<BR>\n" );
document.write( ".<BR>\n" );
document.write( "what is the minimum value?<BR>\n" );
document.write( "f(x)=3x^2-9x+7<BR>\n" );
document.write( "f(1.5)=3(1.5^2)-9(1.5)+7<BR>\n" );
document.write( "f(x)= .25 </SPAN>\n" );
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