document.write( "Question 288873: A practice pool is 10 meters long by 5 meters
\n" ); document.write( "wide by 4 meters deep. Water is filling
\n" ); document.write( "the pool at a rate of 10 gallons per minute.
\n" ); document.write( "When the pool is half full how fast is the water
\n" ); document.write( "rising (in meters/minute)?
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Algebra.Com's Answer #209352 by Alan3354(69443)\"\" \"About 
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A practice pool is 10 meters long by 5 meters
\n" ); document.write( "wide by 4 meters deep. Water is filling
\n" ); document.write( "the pool at a rate of 10 gallons per minute.
\n" ); document.write( "When the pool is half full how fast is the water
\n" ); document.write( "rising (in meters/minute)?
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\n" ); document.write( "1 gallon =~ 3.7854 liters
\n" ); document.write( "10 gal/min = 37.854 liters/min = 37854 cc/min
\n" ); document.write( "The cross-sectional area = 50 sq meters = 500000 sq cm
\n" ); document.write( "Level change = 37854/500000 cm/min
\n" ); document.write( "= 378.54/500000 meters/min
\n" ); document.write( "= 7.5708E-4 meter/min
\n" ); document.write( "or 0.000757 meters/min
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\n" ); document.write( "This is the level change at any point, being half full is not relevant, nor is the depth of the pool.
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\n" ); document.write( "Tho it might seem like a lot of math, there's only one division (by 5) and a lot of moving of the decimal point. Unlike using feet, inches, gallons, furlongs, etc.\r
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