document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34598>Question 34598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the quadratic formula.  Show all the steps,otherwise no credit:  2x2 -8x -3 = 0.  Please help me with this problem.  I have no idea how to do it.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20934 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x~2-8x-3=0 or using the quadric formula (-b+/-sqrt(b~2-4ac))/2a\r<BR>\n" );
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document.write( "we get (-(-8)+/- sqrt (-8*-8-4*2*-3))/4 or (8+/-sqrt(64+24))/4 or \r<BR>\n" );
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document.write( "(8+/- sqrt 88)/4 or (8+2sqrt11)/4 or (4+sqrt11)/2 or (8-2sqrt11)/4 or <BR>\n" );
document.write( "(4-sqrt11)/2 </SPAN>\n" );
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