document.write( "Question 288902: Find 2 consecutive positive odd intergers whose product is 143. \n" ); document.write( "
Algebra.Com's Answer #209336 by mananth(16946)\"\" \"About 
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let the numbers be x, and x+2\r
\n" ); document.write( "\n" ); document.write( "x(x+2)=143\r
\n" ); document.write( "\n" ); document.write( "x^2+2x-143=0\r
\n" ); document.write( "\n" ); document.write( "x^2+13x-11x-143=0\r
\n" ); document.write( "\n" ); document.write( "x(x+13)-11(x+13)=0\r
\n" ); document.write( "\n" ); document.write( "(x+13)(x-11)=0\r
\n" ); document.write( "\n" ); document.write( "x= -13 or 11\r
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\n" ); document.write( "\n" ); document.write( "The numbers can be 11 & 13 or -13, -11\r
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