document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34653>Question 34653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried this problem, but just can't solve it!\r<BR>\n" );
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document.write( "To avoid hitting any rocks below, a cliff diver jumps up and out. The equation h= -16t(the t is squared) + 4t + 26 decribes her height, h, in feet t seconds after jumping. Find the time at which she returns to a height of 26 feet. \r<BR>\n" );
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document.write( "I tried:\r<BR>\n" );
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document.write( "26 = -16t(squared) + 4t =26, but can't figure out how to solve </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20930 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Subtract 26 from both sides to get:<BR>\n" );
document.write( "-16t^2+4t=0<BR>\n" );
document.write( "-4t(4t-1)=0<BR>\n" );
document.write( "t=0 or t=1/4<BR>\n" );
document.write( "At time 0 and at time 1/4 sec. she is at the 26 ft level.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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