document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288802>Question 288802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Objective: Apply the Pythagorean Theorem\r<BR>\n" );
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document.write( "The width of a rectangle is 1 and its perimeter is 14. Find the measure of a diagnonal of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209284 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Pythagorean Theorem states: a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "If the perimeter is 14 and the width is 1, then the length must be 6.\r<BR>\n" );
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document.write( "Let a = 6\r<BR>\n" );
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document.write( "Let b = 1\r<BR>\n" );
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document.write( "We are looking for c.\r<BR>\n" );
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document.write( "Here is the set up and you can finish.\r<BR>\n" );
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document.write( "(6)^2 + (1)^2 = c^2 </SPAN>\n" );
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