document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288709>Question 288709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My issue if finding a LCM to this equation. My teacher didn't explain it very well, however, I think AFTER obtaining the LCM I understand how to solve the equation. This particular problem is: \r<BR>\n" );
document.write( "\n" );
document.write( "7/(x-3) - (2/7) = -10/(3x-9) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209275 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7/(x-3) - (2/7) = -10/(3x-9)<BR>\n" );
document.write( "[7*7-2(x-3)]/7(x-3)=-10/(3x-9)<BR>\n" );
document.write( "[49-2x+6]/(7x-21)=-10/(3x-9)<BR>\n" );
document.write( "[-2x+55]/(7x-21)=-10/(3x-9) cross multiply.<BR>\n" );
document.write( "-10(7x-21)=(3x-9)(-2x+55)<BR>\n" );
document.write( "-70x+210=-6x^2+18x+165x-495<BR>\n" );
document.write( "-70x+210=-6x^2+183x-495<BR>\n" );
document.write( "6x^2-70x-183x+210+495=0<BR>\n" );
document.write( "6x^2-253x+705=0<BR>\n" );
document.write( "(6X-235)(X-3)=0<BR>\n" );
document.write( "6X-235=0<BR>\n" );
document.write( "6X=235<BR>\n" );
document.write( "X=235/6 ANS.<BR>\n" );
document.write( "X-3=0<BR>\n" );
document.write( "X=3 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "7/(x-3) - (2/7) = -10/(3x-9)<BR>\n" );
document.write( "7/[(235/6)-3]-2/7=-10/[(3*235/6)-9]<BR>\n" );
document.write( "7/[(235-3*6)/6]-2/7=-10/[(705/6)-9]<BR>\n" );
document.write( "7/[217/6]-2/7=-10/[705-9*6]/6<BR>\n" );
document.write( "7*6/217-2/7=-10/[705-54]/6<BR>\n" );
document.write( "42/217-2/7=-10/[651]/6<BR>\n" );
document.write( ".1935-.2857=-10*6/651<BR>\n" );
document.write( "-.0922=-60/651<BR>\n" );
document.write( "-.0922=-.0922<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );