document.write( "Question 288741: length of a rectangle is 8 in less than twice the width. the area is 90 in squared find the width \n" ); document.write( "
Algebra.Com's Answer #209263 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-8 \n" ); document.write( "AREA=LW \n" ); document.write( "90=(2W-8)W \n" ); document.write( "90=2W^2-8W \n" ); document.write( "2W^2-8W-90=0 \n" ); document.write( "2(W^2-4W-45)=0 \n" ); document.write( "2(W-9)(W+5)=0 \n" ); document.write( "W-9=0 \n" ); document.write( "W=9 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*9-8 \n" ); document.write( "L=18-8 \n" ); document.write( "L=10 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "90=10*9 \n" ); document.write( "90=90 \n" ); document.write( " |