document.write( "Question 288741: length of a rectangle is 8 in less than twice the width. the area is 90 in squared find the width \n" ); document.write( "
Algebra.Com's Answer #209263 by checkley77(12844)\"\" \"About 
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L=2W-8
\n" ); document.write( "AREA=LW
\n" ); document.write( "90=(2W-8)W
\n" ); document.write( "90=2W^2-8W
\n" ); document.write( "2W^2-8W-90=0
\n" ); document.write( "2(W^2-4W-45)=0
\n" ); document.write( "2(W-9)(W+5)=0
\n" ); document.write( "W-9=0
\n" ); document.write( "W=9 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*9-8
\n" ); document.write( "L=18-8
\n" ); document.write( "L=10 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "90=10*9
\n" ); document.write( "90=90
\n" ); document.write( "
\n" );