document.write( "Question 288736: How much of a 10% saline solution should be mixed with a 20% saline solution to obtain 1000 milliters of a 12% saline solution?
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document.write( "Use a system of equations and substitution to solve each problem.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #209244 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! A single equation is a much simplier method. \n" ); document.write( ".20x+.10(1,000-x)=.12*1,000 \n" ); document.write( ".20x+100-.10x=120 \n" ); document.write( ".10x=120-100 \n" ); document.write( ".10x=20 \n" ); document.write( "x=20/.10 \n" ); document.write( "x=$200 invested @ 20%. \n" ); document.write( "1,000-200=$800 invested @ 10%. \n" ); document.write( "Proof: \n" ); document.write( ".20*200+.10*800=.12*1,000 \n" ); document.write( "40+80=120 \n" ); document.write( "120=120 \n" ); document.write( " |