document.write( "Question 288736: How much of a 10% saline solution should be mixed with a 20% saline solution to obtain 1000 milliters of a 12% saline solution?
\n" ); document.write( "Use a system of equations and substitution to solve each problem.
\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #209244 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
A single equation is a much simplier method.
\n" ); document.write( ".20x+.10(1,000-x)=.12*1,000
\n" ); document.write( ".20x+100-.10x=120
\n" ); document.write( ".10x=120-100
\n" ); document.write( ".10x=20
\n" ); document.write( "x=20/.10
\n" ); document.write( "x=$200 invested @ 20%.
\n" ); document.write( "1,000-200=$800 invested @ 10%.
\n" ); document.write( "Proof:
\n" ); document.write( ".20*200+.10*800=.12*1,000
\n" ); document.write( "40+80=120
\n" ); document.write( "120=120
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