document.write( "Question 288736: How much of a 10% saline solution should be mixed with a 20% saline solution to obtain 1000 milliters of a 12% saline solution?
\n" ); document.write( "Use a system of equations and substitution to solve each problem.
\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #209241 by texttutoring(324)\"\" \"About 
You can put this solution on YOUR website!
Let V1 = the volume of the 10% solution.
\n" ); document.write( "Let V2= the volume of the 20% solution.\r
\n" ); document.write( "\n" ); document.write( "Working in Litres (1 Litre = 1000mL), and decimals instead of percents (i.e. 12%=0.12)\r
\n" ); document.write( "\n" ); document.write( "Eqn 1: 0.10*V1 + 0.20*V2 = 0.12*1.0
\n" ); document.write( "Eqn 2: V1 + V2 = 1.0 L\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Isolate V2 in equation 2:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "V2 = 1 - V1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Substitute this value for V2 into Eqn 1:\r
\n" ); document.write( "\n" ); document.write( "0.10*V1 + 0.20(1-V1) = 0.12
\n" ); document.write( "-0.10*V1 + 0.20 = 0.12
\n" ); document.write( "-0.10*V1 = -0.08
\n" ); document.write( "V1 = 0.8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Eqn 2 tells us that V1 + V2 must equal 1.00 Litres\r
\n" ); document.write( "\n" ); document.write( "Therefore V2=1-0.8\r
\n" ); document.write( "\n" ); document.write( "V2=0.2 L\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So you would need 800 mL (0.8 L) of the 10% solution and 200mL (0.2L) of the 20% solution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps. If you have any questions, just let me know!
\n" ); document.write( "
\n" );